Multiple Choice Questions On Aptitude With Explanation

1)A man buys an article for Rs. 27.50 and sells it for Rs. 28.60. What will be his gain percent   ?

1. 10%
2. 4%
3. 3%
4. 1%

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Answer = B
Explanation:
C.P = 27.50
S.P = 28.60
Gain = Rs(28.60 - 27.50) = 1.10
Gain % = ( (1.10 / 27.50 ) * 100 )% = 4%

2) If the radio is purchased for Rs 490 and sold for Rs. 465.50 then what is the Loss percent?

1. 50%
2. 20%
3. 10%
4. 5%

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Answer = D
Explanation:
C.P = 490
S.P = 465.50
Loss = Rs(490 - 465.50)= Rs 24.50
Loss % = ((24.50/490)*100)% = 5%

3) By selling a book for Rs. 115.20, a man losses 10%. At what price should he sell it to gain 5% ?

1. 150
2. 143.50
3. 134.40
4. 134.42

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Answer = C 
Explanation: 
Let the new S.P be Rs x
(100 - loss%) : (1st SP) = (100 + gain%) : (2nd SP)
                  or
=> (100 - 10) / 115.20 = (100 + 5) / x
=>  x = (105 * 115.20)/90 = 134.40

4) A trader lost 20% by selling a watch for Rs. 1024 What percent shall he gain or loss by selling it for Rs. 1472  ?

1. 23%
2. 15%
3. 32%
4. 43%

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Answer = B 
Explanation: 
Let the gain % be x
=> 80 : 1024 = (100 + x) : 1472
=> 80 / 1024 = (100 +x) / 1472
=> 100+x = (80 * 1472) / 1024 
=> 100+x = 115
=> x = 15
Hence gain% = 15%

5) Hari purchased 25kg of wheat at Rs 4 per Kg and 35 Kg of wheat at Rs 4.50 per Kg. He sold the mixture at Rs 4.25 per Kg. Find his gain or loss ?

1. 3.50
2. 4.50
3. 5.50
4. 2.50

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Answer = D 
Explanation: 
Total C.P = Rs (25*4 + 35*4.50)
               = Rs. 257.50
Total S.P = Rs (60*4.25) 
               = Rs 255
Loss = Rs ( 257.50 - 255 ) = Rs. 2.50

6) A man sells an article at a profit of 25%. If he had bought it at 20% less and sold it for Rs. 10.50 less, he would have gained 30%. Find the cost price of the article ?

1. 50
2. 60
3. 70
4. 80

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Answer = A 
Explanation: 
Let the C.P be Rs x
1st S.P = 125% of Rs x = (125 / 100 )x = 54 / x
2nd C.P = 80% of x = (80/100)x=(4/5)x
2nd S.P= 130% of (4/5)x= (130/100)*(4/5)x = (26 / 25)x
Hence  (5/4)x - (26/25)x = 10.50
        => x = (10.50*100) / 21
                = 50

7) A Grocer purchased 80Kg of rice at Rs 13.50 per Kg and mixed it with 120Kg of rice at Rs. 16 per Kg. At what rate per Kg should he sell the mixture to gain 16% ?

1. 20.00
2. 17.40
3. 18.56
4. 34.67

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Answer = B 
Explanation: 
C.P of 200 Kg of mix = Rs(80 * 13.50 + 120 * 16) = Rs. 3000
S.P = 116% of Rs.3000 = Rs (116/100) * 3000 = Rs. 3480
Rate of S.P of the mixture = Rs(3480/200) per Kg = Rs 17.40 per Kg

8) A vender sells 10 toffees for a rupee, gaining thereby 20%. How many did he buy for a rupee ?

1. 15
2. 10
3. 12
4. 20

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Answer =C 
Explanation: 
S.P of 10 toffees = Re 1, gain = 20%
Re 5 / 6 is C.P of 10
Re 1 is the C.P of ( 10 * (6/5)) = 12
Hence he bought 12 toffees for a rupee

9) A trader allows discount of 10% on the marked price and allows a discount of 15% on it. Find his gain percent ?

1. 1%
2. 2%
3. 3%
4. 5%

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Answer = B 
Explanation: 
Let C.P = Rs. 100 Then marked price = 120
so S.P = 85% of Rs 120 = Rs 102
Hence gain% = 2%

10) A shopkeeper allows  a discount of 10% on the marked price. How much above cost price must he mark his goods to gain 8% ?

1. 120
2. 140
3. 200
4. 250

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Answer = A 
Explanation: 
Let C.P = Rs. 100 Then S.P = Rs 108
Let marked price be Rs x
=>  90% of x = 108
=> x = (108 ) * (100/90) = 120
Hence Marked price = Rs. 120

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Multiple Choice Questions On Aptitude | UGC NET Exam 2012 Sample

1)  A die is tossed once. What is the probability of getting an odd number?

1. 1/3
2. 1/2
3. 1
4. 3/4

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Answer = B 
Explanation:We know that the sample space for a die tossed once is { 1, 2, 3, 4, 5, 6} out of which {1, 3, 5} are odd numbers. So the p(getting an odd number)= (Favorable cases/Total cases) = 3/6 = 1/2

2) A coin is tossed once. Find the probability of getting a head ?

1. 1/2
2. 3/2
3. 3/4
4. None of above

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Answer = A 
Explanation:We know that sample space for a head tossed once is { head, tail} out of which head comes only once so the  P(getting head) = 1/2

3) A Bag contains 8 red, 7 white, 6 black balls. Find the probability of getting a black ball ?

1. 1
2. 6/8
3. 6/7
4. 2/7

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Answer =D 
Explanation:
Here Total number of balls are: 21
We have to find the probability of black ball and number of black balls are 6.
So the P(black ball) = 6/21 = 2/7
                                

4)  A bag contains 2 red, 8 black, and 7 white balls. Find the probability of not getting a white ball ?

1. 7/10
2. 7/8
3. 10/17
4. None

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Answer = C 
Explanation: 

Total balls=17
White balls = 7
P(white ball) = 7/17
P(Not white ball) = 1 - (7/17) = 10/17

5) Given that E and F are two events such that P(E) = 0.6, P(F) = 0.3 and P(E and F) = 0.2, Then what is the value of P(E/F)  ?

1. 2/3
2. 1/3
3. 1
4. None

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Answer = A 
Explanation: 

P(E/F) = P(E and F) / p(E) 
          = 0.2 / 0.3 
          = 2 / 3

6) A four digit number is formed, using the digits 1,2,3,5 with no repetitions. The probability that the number is divisible by 5 ?

1. 4/5
2. 1/4
3. 3/4
4. Can't say

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Answer = B 
Explanation: 

Let m be the favorable cases = Numbers of four digit which are divisible by 5 = 6
Let n be the total number of cases = ⁴C₄ = 24
Required Probability = 6/24 = 1/4

7) A coin is tossed twice. What is the probability that the head occurs at least once ?

1. 4/4
2. 2/4
3. 3/4
4. 0

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Answer = 3/4 
Explanation:

As a coin is tossed twice so sample space = {  HH , HT , TH , TT} Where H = head and T= tail
Sample space for favorable cases that the head occurs at least once = (HH, HT, TH}
Reqd. Probability = 3/4

8) A Coin is tossed twice. Find the probability that the head occurs at most once ?

1. 3/4
2. 1/4
3. 2/4
4. None

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Answer =  A
Explanation:

Sample space = {HH, HT, TH, TT}
Favorable cases = {HT, TH , TT}
P(Head occurs at most once) = 3/4 

9) Let E and F are two events. P(E) = 0.2, What is P(F) ?

1. can't be findable
2. 1
3. 2
4. 0.8

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Answer = D 
Explanation: 

As we know that the total probability of all the events = 1
P(One event)=0.2
P(second event)=1 - 0.2
                        = 0.8

10)  A die is thrown thrice. Then the total number of cases will be?

1. 3
2. 6
3. 8
4. 216

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Answer = D 
Explanation:
Total number of cases will be = 6 * 6  * 6 = 216

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